If 3,600 J of work is done in 3. 0 s, what is the power? 0. 00083 W 1,200 W 3,600 W 11,000 W.
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The magnitude of the average total force acting on the object during this time interval is equal to 20 Newton.
<u>Given the following data:</u>
- Mass = 2.0 kg
- Initial velocity = 30 m/s
- Final velocity = 40 m/s
- Time = 5.0 seconds.
- Angle = 90°
To calculate the magnitude of the average total force acting on the object during this time interval:
<h3>Newton's Second Law of Motion</h3>In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.
<u>Note:</u> The acceleration of an object is equal to the rate of change in velocity with respect to time.
Mathematically, Newton's Second Law of Motion is given by this formula;
Substituting the given parameters into the formula, we have;
Force A = 12 Newton.
<u>For the second force:</u>
Force B = 16 Newton.
Now, we can calculate the magnitude of the average total force acting on the object during this time interval:
Total force = 20 Newton.
Read more on force here: brainly.com/question/1121817