I am interested in TRIO because TRIO programs offer academic tutoring, personal counseling, mentorship, financial assistance, and other services to help students get into and stay in school. TRIO programs provide students with direct help as well as essential training for directors and staff.
[ You fill in your future goals ]
TRIO SSS is aimed to create a supportive network for kids from underprivileged communities. It offers comprehensive programs that enhance academic, personal, and professional development, as well as financial aid and financial literacy help. These studies show that enrolling in a TRIO program has a substantial influence on the educational results of low-income, first-generation, and disabled students.
Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
The weight percent is of caffiene is 7.98%.
There are several ways of expressing concentration in chemistry. One of the methods of expressing concentration is by the use of percentage.
In this case, we want to obtain the percent weight/weight concentration of caffeine in benzene.
From the question, we can see that;
Mass of solute = 6.5 g
Mass of solvent = 75 g
percent w/w = mass of solute/ mass of solute + mass of solvent × 100/1
percent weight of caffeine=
6.5/6.5 + 75 × 100/1 =7.98%
Learn more: brainly.com/question/19953404
