2(x-6y+4z=2)
2x+4y-8z=16
2x-12y+8z=4
2x+4y-8z=16
4x-8y=20
x-2y=5
4x-8y=20
-4x+8y=-20
infinite many solutions
Answer:
y - 0 = -3/4(x - 8)
y = -3/4x + 6
Step-by-step explanation:
C^2-a^2=b^2 b^2=81-36=45 x^2/36-y^2/45=1?
The answer is 4 m/s.
In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).
The relation of speed (v), distance (d), and time (t) can be expressed as:
v = d/t
We need to calculate the speed of the second 5 seconds of the travel:
d = 20 m (total 30 meters - first 10 meters)
t = 5 s (time from t = 5 seconds to t = 10 seconds)
Thus:
v = 20m / 5s = 4 m/s
