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2 years ago

Determine whether each equation is a linear equation. Write yes or no. If yes, write the equation in standard form. y = 4x + x

Mathematics

1 answer:

DochEvi [55]2 years ago

4 0

Answer:

y = 4x + x is a linear equation

Step-by-step explanation:

A linear equation has the general equation as below;

${ \bf{y = mx + k}}$

k is a constant.

• For y = 4x + x

y = 5x

m is 5 and k is 0

${ \underline{ \mathfrak{ \green{Good \: grace}} \: \:⚜ \: \: { \blue{ \mathfrak{Good \: God}}}}}$

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Both fractions in the expression of 1/3 +1/3 are examples of...

kirza4 [7]

Equivalent fractions

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2 years ago

On a long distance bike trip Annike started at 7 a.m and her average speed was 11 miles per hour and Celia travels 14 miles per

Troyanec [42]

Answer:

Annike's bike trip started at 7:00, if she and Celia both start at the same time you would multiply Annike's average speed by Celia's average speed to find where they would have completed the same number of miles

equation: 11×14=154 14×11=154

Step-by-step explanation:

counting by 11:

11 22 33 44 55 66 77 88 99 110 121 132 143 154

11 × 14 = 154

counting by 14:

14 28 42 56 70 84 98 112 126 140 154

14 × 11 = 154

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3 years ago

In the same area where there are 3 Mankey Pokemon, 4 Pidgey Pokemon, and 2 Rattata Pokemon. What would be the probability of run

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The probability of you running into a Mankey Pokemon and then a Pidgey Pokemonis 4/27.

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1 year ago

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one

RSB [31]

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one loan for $3000 repayable in 12 months?

He took two different loans, it charged him loan processing fee twice, two-time documentation process, and of course, extra time spent for second loan. Instead, he could take single loan of $3000 with one-time processing fee, one-time documentation process, and time-saving also.

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2 years ago

A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res

Alexus [3.1K]

Answer:

Step-by-step explanation:

Hello!

So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:

X: "Lifetime of one shoe pair of the new model"

Applying CLT:

X[bar]≈N(μ;σ²/n)

Known values:

n= 30 shoe pairs

x[bar]: 17 months

S= 5.5 months

Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:

H₀:μ=15

H₁:μ≠15

The significance level for the test is given: α: 0.05

Your critical region will be two-tailed:

$Z_{\alpha /2} = Z_{0.025}= -1.96$

$Z_{1-\alpha /2} = Z_{0.975}= 1.96$

So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96

Now you calculate your observed Z-value

Z=x[bar]-μ ⇒ Z= 17-15 = 1.99

σ/√n 5.5/√30

Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.

I hope you have a SUPER day!

5 0

3 years ago