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beks73 [17]
3 years ago
9

The Taco Shop sold 198 lunches Friday. This number is 3 more than 3 times the number they sold Monday. Let n represent the numbe

r of lunches sold Monday.Which equation shows an equality between two different ways of expressing the number of lunches sold on Friday?
A.n – 3 = 198

B.3n – 3 = 198

C.3n + 3 = 198

D.n + 3 = 198
Mathematics
1 answer:
scoundrel [369]3 years ago
4 0
C
3 times Monday plus 3
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of the 400 vehicles that passed the intersection, 98 are buses, what percent of the vehicles that passed the intersection are bu
frutty [35]
It should be 24.5%. If you divide 98 by 400 it's .245. Then multiply it by 100, you get 24.5%.
5 0
3 years ago
A builder was building a fence. In the morning, he worked for 2/5 of an hour. In the afternoon, he worked for 9/10 of an hour. H
guajiro [1.7K]

Answer:believe it’s 12

Step-by-step explanation:

3 0
3 years ago
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
Hcf of 60 and 36 <br><br> Please help meeee meow
ziro4ka [17]
12,24,(36),48,(60),72,84….
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5 0
2 years ago
May I have help on This question please I’ll award you brainliest
BartSMP [9]

Answer:

The top right answer choice is correct.

2.3 x 12 = 27.6

27.6 > 27.1

Step-by-step explanation:

Well first off, we know that:

1 foot = 12 inches

To compare the two, we first want to covert 2.3 feet into inches.

2.3 x 12 = 27.6 inches

Now that we have our two values, we need to decide which is greater than the other.

27.6   or    27.1

Both values have a decimal that shows tenths. In this problem, 6 tenths is larger than 1 tenth. Therefore:

27.6 inches > 27.1 inches

5 0
3 years ago
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