Answer:
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Step-by-step explanation:
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Answer:
e.none of these
Step-by-step explanation:
Computations For CC for Fraction defective
Sample No d p=d/100
1 0 0
2 0 0
3 2 0.02
4 1 0.01
5 0 0
6 1 0.01
7 2 0.02
8 0 0
Total 0.06
![\overline{p} =\frac{1}{k}\sum p=\frac{0.06}{8} =0.0075](https://tex.z-dn.net/?f=%5Coverline%7Bp%7D%20%3D%5Cfrac%7B1%7D%7Bk%7D%5Csum%20p%3D%5Cfrac%7B0.06%7D%7B8%7D%20%3D0.0075)
![\overline{q} =1- 0.0075= 0.9925](https://tex.z-dn.net/?f=%5Coverline%7Bq%7D%20%3D1-%200.0075%3D%200.9925)
3 sigma control limits for p chart are given by:
![\overline{p} \pm 3\sqrt{\overline{p}\overline{q}/n}\Rightarrow 0.0075\pm 3\sqrt{\frac{0.0075*0.9925}{100}}](https://tex.z-dn.net/?f=%5Coverline%7Bp%7D%20%5Cpm%203%5Csqrt%7B%5Coverline%7Bp%7D%5Coverline%7Bq%7D%2Fn%7D%5CRightarrow%200.0075%5Cpm%203%5Csqrt%7B%5Cfrac%7B0.0075%2A0.9925%7D%7B100%7D%7D)
![= 0.0075\pm0.0259\Rightarrow ( 0.0334,0 )](https://tex.z-dn.net/?f=%3D%200.0075%5Cpm0.0259%5CRightarrow%20%28%200.0334%2C0%20%29)
hence option e is correct
Answer:
Flour used to make 9 pizzas = 5
× ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
= 3![\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D)
Flour used for each pizza = 3
÷ 9
= 3
×
(reciprocal of 9)
= ![\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D)
The amount of flour used for each mini pizza is
kg.
Answer:
Ello mate, the answer to your question/problem is "J"
Step-by-step explanation: Look at image provided below :)
Top row: 0, 45, 90, 135, 180, 225, 270, 315, 360, 405, 450, 495, 540
Bottom row: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12