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3 years ago

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Mathematics

1 answer:

erica [24]3 years ago

3 0

Step-by-step explanation:

1. Not all rational numbers are whole numbers. Whole numbers can be rational numbers, if expressed in fraction form. For example, 1 can be expressed as $\frac{1}{1}$ . A set of rational numbers consists of a set of numbers written as a quotient of two integers, a and b, in the form $\frac{a}{b}$ , where b ≠ 0. The reason why b ≠ 0 because division by zero is an undefined mathematical operation.

2. Irrational numbers differ from rational numbers in terms of its representation: while the rational numbers can be expressed as a ratio or in fraction form, irrational numbers cannot be expressed in fraction form.

Irrational numbers are a set of numbers for which its decimal representations is neither terminating, nor repeating. A couple examples of irrational numbers are: π and $\sqrt{2}$ , as their decimal representations do not come to an end and doesn't have a block of repeating digits.

3. All real numbers are rational numbers. Real numbers comprise of natural numbers, whole numbers, integers, rational numbers, and irrational numbers.

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So 14 is 2 times 7 or 1 times 14 so the factors are
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The GCF of 72 and 36 is: 36

List out the factors of each number (72 and 36), and find the common factors between the two numbers.

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
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Looking at the factors above, the common ones are 1, 2, 3, 4, 6, 9, 12, 18, and 36. But... considering we are looking for the "greatest" common factor, our highest number out of the listed ones is 36, making it the greatest common factor of 72 and 36.

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3 years ago

What percent of forty-eight is thirty?

UNO [17]

Answer:

P = 62.5 %

Step-by-step explanation:

Of means multiply and is means equals

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4 years ago

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Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

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Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

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$\sqrt{8x^7y^8$

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$\sqrt{8*x^7*y^8$

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$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

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$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

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$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

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