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9966 [12]
2 years ago
5

9. Here are two expressions with a missing number:

Mathematics
1 answer:
ELEN [110]2 years ago
4 0
Use the sr(3)

All the other options are rational 32/10, 2/3, 23/99.
Multiplying two fractions is always rational.
Adding 4 to a rational number will also be rational.
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3. A large fruit dish with a 36 in. diameter is placed in the center of a banquet across and is completely filled with apples. T
Serga [27]

Answer:

a) 11%

b) 56%

Step-by-step explanation:

a) A= πr^2    6^2π= 36π    A= 18^2π = 324π

36π/324π = .111111111111111111111111 or 11%

remember to cancel out the pi symbols when you are showing your work

(put a line across the pi symbols when dividing)

b)   A= πr^2         18^2 π = 324π

     A= πr^2          12^2π = 144π  

              324 – 144  = 180

180π/324π = .5555555555555555555555556 or 56%

remember to cancel out the pi symbols when you are showing your work

(put a line across the pi symbols when dividing)

3 0
3 years ago
Brainiest will be given . Please help me
mixas84 [53]

Answer:

If the shape of end face has n sides

Then, in total, there are n+2 faces

Using that formula

Faces in 20-sided polygon = n+2 = 20+2 = 22

Step-by-step explanation:

Pls vote as brainliest

6 0
2 years ago
4.<br> The probability of it raining tomorrow is 0.34. What is the probability it doesn't<br> rain?
ELEN [110]

Answer:

99.66%

Step-by-step explanation:

4 0
2 years ago
Don’t troll I need a answer!
Andre45 [30]
A)(2x+48x)-7 (6x•9x)+32
6 0
3 years ago
Read 2 more answers
The nth term of a sequence is 3n^2- 1
Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √(  (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √(  (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √(  (31 - 2^2)/3)  = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0
2 years ago
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