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3 years ago

What is 6 1/2 + 9 3/8

Mathematics

2 answers:

san4es73 [151]3 years ago

4 0

Answer:

the answer is 15 7/8

Tatiana [17]3 years ago

4 0

Answer: 15 7/8

Step-by-step explanation:

Add the whole numbers first 6+9 to getting 15

Now find the lowest common denominator for both the fractions. In this case it is 8.

3/8 would stay the same however 1/2 would become 4/8. 4/8 + 3/8 is 7/8.

15 add 7/8 is 15 7/8

You might be interested in

How do I graph a function based off the unit circle?

sweet [91]

So if you remember what the normal y = sin(x) function looks like (a wave), y = 2 sin(4x) is just changed a little.

The standard format for sine/cosine function
y = a sin(bx− c) + d

a = amplitude, distance from center of the wave to the highest point. This function a = 2 so the height of the sine wave reaches 2 instead of 1.
"c" and "d" shift the graph left/right and up/down respectively. These equal zero so the sine wave is not shifted.

The range (y-values) is then just the amplitude -2 ≤ y ≤ 2

The domain (x-value) is all real numbers because the wave just keeps going on to infinity in both directions.

2π / |b| = period, distance per wave
this equation b = 4
period is then π/2
this is the distance before a wave repeats.

Graph
 x | y
-π/8 -2
 0 0
π/8 2
3π/8 -2
5π/8 2

see the pattern? I'm using the amplitude or peaks and bottoms of the wave y = 2 and -2 then using the x-distance between like points is the period so you add π/2

(π/8 , 2)
+ π/2
(5π/8 , 2)

Same for the minumums of the wave (y = -2)
(-π/8 , -2)
+ π/2
(3π/8 , -2)

Hope this helps, otherwise there are youtube videos you can watch or try an online graphing calculator like Desmos.com

7 0

3 years ago

if bill puts $3,500 into an account that has a 2.5% interest rate compounded annually, how much money will bill have after 3 yea

lyudmila [28]

Answer:

$26,250

Step-by-step explanation:

$3,500×(2.5)^3

8 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

uysha [10]

Answer:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

Step-by-step explanation:

For this problem we have the following data given:

$\bar X_1 = 9$ represent the sample mean for one of the departments

$\bar X_2 = 8$ represent the sample mean for the other department

$n_1 = 25$ represent the sample size for the first group

$n_2 = 20$ represent the sample size for the second group

$s_1 = 2$ represent the deviation for the first group

$s_2 =1$ represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

The confidence given is 95% or 9.5, then the significance level is $\alpha=0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df=n_1 +n_2 -2= 20+25-2= 43$

And the critical value for this case is $t_{\alpha/2}=2.02$

And replacing we got:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

4 0

3 years ago

two mechanics worked on a car. The first mechanic worked for 10 hrs, and the second mechanic worked for 5 hours. Together they c

soldier1979 [14.2K]

Answer:

The first mechanic $90/hour and the second charged $70/hour

Step-by-step explanation:

Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:

5x+10y = 1150

We also know that together they charged 160/per hour. An equation to express this would be:

x+y = 160

Now we can solve the second equation for x or the first mechanics rate.

x+y = 160

x = 160 - y

Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.

5x+10y=1150 plug in x =160-y

5(160-y)+10y=1150 Distribute

800 -5y+10y = 1150 Combine like terms

800 +5y = 1150 Subtract 800 from both sides

5y = 350 divide by 5

y = 70

So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.

x = 160-y

x = 160-70

x = 90

So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.

5 0

3 years ago

Don't worry about the pics at the bottom plz help

TiliK225 [7]

First one: x>5
second one: x≥5
im pretty sure its right
Hope this helps love! :)

6 0

3 years ago