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PSYCHO15rus [73]
3 years ago
15

Find the circumference of the object Use 3.14 or 22 for for T. Round to the nearest hundredth if necessary 11.4 in. The circumfe

rence is about inches​

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

35.80

Step-by-step explanation:

3.14 \times 11.4 = 35.796

Simplify & Round

35.796 ---> 35.80

Awnser = 35.80

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zheka24 [161]

Answer:

Step-by-step explanation:

9x6x12= 648 the length(12m), width(6m), and height(9m) that all i can give you for now because this got me losing brain sells

5 0
3 years ago
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The fraction 5/8 is located between what two fractions?
S_A_V [24]
C is the answer I pretty sure of it
8 0
3 years ago
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Solve the following compound inequality 4
CaHeK987 [17]

Answer:

0 < x < 8

Step-by-step explanation:

Given

4 < x + 4 < 12

Required

Solve

4 < x + 4 < 12

Split:

4 < x + 4  and  x + 4< 12

Collect Like Terms

4 - 4 < x and x < 12- 4

0 and x < 8

Combine

0 < x < 8

7 0
3 years ago
Mr Smith's art class took a bus trip to an art museum. The bus averaged 65 miles per hour on the highway and 25 miles per hour i
Leya [2.2K]
Let x be the distance traveled on the highway and y the distance traveled in the city, so:
\left \{ {{x+y=375} \atop { \frac{1}{65}x+ \frac{1}{25}y =7}} \right.
 
Now, the system of equations in matrix form will be:
\left[\begin{array}{ccc}1&1&\\ \frac{1}{65} & \frac{1}{25} &\end{array}\right]   \left[\begin{array}{ccc}x&\\y&\end{array}\right] =  \left[\begin{array}{ccc}375&\\7&\end{array}\right]

Next, we are going to find the determinant:
D=  \left[\begin{array}{ccc}1&1\\ \frac{1}{65} & \frac{1}{25} \end{array}\right] =(1)( \frac{1}{25}) - (1)( \frac{1}{65} )= \frac{8}{325}
Next, we are going to find the determinant of x:
D_{x} =  \left[\begin{array}{ccc}375&1\\7& \frac{1}{25} \end{array}\right] = (375)( \frac{1}{25} )-(1)(7)=8

Now, we can find x:
x=  \frac{ D_{x} }{D} = \frac{8}{ \frac{8}{325} } =325mi

Now that we know the value of x, we can find y:
y=375-325=50mi

Remember that time equals distance over velocity; therefore, the time on the highway will be:
t_{h} = \frac{325}{65} =5hours
An the time on the city will be:
t_{c} = \frac{50}{25} =2hours

We can conclude that the bus was five hours on the highway and two hours in the city. 

8 0
3 years ago
Theo is a cleaner,
GaryK [48]

Step-by-step explanation:

1 hour 50 minutes = 110 mins

1 1/2 hours = 90 mins

add all these:

110

90

85

55

35

when you add all these you get 375

every hour has 60 minutes

375 ÷ 60 = 6.15

if he starts at 9 am and he cleans for 6.15 hours he will be finished by 3:15pm.

4 0
2 years ago
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