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marishachu [46]
2 years ago
5

I don't understand this question. Could someone help me? The graph is what is being looked at. I've already tested if they are o

btuse, that's incorrect.

Mathematics
1 answer:
Alex Ar [27]2 years ago
5 0

The answer should be obtuse. I'm not sure why it is saying it's incorrect but none of the other answers make sense.

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Dovator [93]

Answer:

109 is the correct answer

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56y - 8 in Distributive Property
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Answer:

8 ( 7 − 1 )

Step-by-step explanation:

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HELP I NEED HELP FAST. ILL MARK YOU BRAINLIEST.
Romashka-Z-Leto [24]

She plays soccer and golf for a total of 125 minutes:

s + g = 125

She plays soccer 45 minutes more than she plays golf:

s = g + 45 this is for A

B= 40 minutes of golf everyday

C= Yes, because in fact, she plays 85 minutes of soccer everyday, and 85 is greater than 80, so yes she CAN play 80 minutes of soccer every day. Perhaps they meant possible to spend ONLY 80 minutes, then NO, that wouldn't be possible, because then by playing 45 minutes more soccer than golf, she wouldn't have played enough to have 125 total minutes of total play. Technically the way the question is worded, the answer is yes.

I hope this helps!

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2 years ago
50 POINTS ANSWER FAST PLEASE
Sholpan [36]

Answer:

Question 2.) 16

144÷9=16

Question 3.) 16

16÷12=1.33... and all the others equal 1.33... as well

Question 4.) 20

20÷16=1.25   and all tho others equal 1.25 as well

Question 5.)12

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6 0
2 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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