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Naya [18.7K]
2 years ago
5

How to determine the volume of a cup?​

Mathematics
1 answer:
snow_lady [41]2 years ago
4 0

Answer:

1 to 8  in cups or 1 to 16 in table spoons

Step-by-step explanation:

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Use substitution to show that 9+ 6(10-7x) is equivalent to 69-42x.
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9 + 60 -42x
9+60 = 69
= 69- 42x
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Find f(-3) PLEASE HELP
Artemon [7]

Answer:

2

Step-by-step explanation:

When the point on the x-axis is on -3, the point on the y-axis is 2. Therefore, f(-3) is equal to 2.

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2 years ago
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YALL NEVER ANSWER AH POOP plz help
lakkis [162]

Answer:

The given point A (6,13) lies on the equation.  True

The given point  B(21,33) lies on the equation.  True

The given point  C (99, 137) lies on the equation.  True

Step-by-step explanation:

Here, the given equation is : y =\frac{4}{3} x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (6) + 5  = 4(2) + 5  = 8 + 5 =  13

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (21) + 5  = 4(7) + 5  = 28 + 5 =  33

⇒ y  = 33

Hence, the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (99) + 5  = 4(33) + 5  = 132 + 5 =  137

⇒ y  = 137

Hence, the given point  C (99, 137) lies on the equation.

7 0
3 years ago
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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

5 0
2 years ago
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