1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naya [18.7K]
3 years ago
5

How to determine the volume of a cup?​

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

1 to 8  in cups or 1 to 16 in table spoons

Step-by-step explanation:

You might be interested in
Please Help!!!!! Bob has completed 72% of the levels on a video game. what fraction of the levels has bob completed? show your w
Nuetrik [128]
How many levels are in the game? You would take that number and multiply it by 0.72 to find 72% of it.
7 0
3 years ago
Read 2 more answers
Find an equation for the perpendicular bisector of the line segment whose endpoints
TEA [102]

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

\boxed{gradient =  \frac{y1 -y 2}{x1 - x2} }

Gradient of given line

=  \frac{1 - ( - 5)}{3 - ( - 9)}

=  \frac{1 + 5}{3 + 9}

=  \frac{6}{12}

=   \frac{1}{2}

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

\boxed{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2})  }

Midpoint of given line

= ( \frac{3  -  9}{2} , \frac{1 - 5}{2} )

= ( \frac{ - 6}{2}  , \frac{ - 4}{2} )

= ( - 3 , - 2)

Substituting (-3, -2) into the equation:

-2= -2(-3) +c

-2= 6 +c

c= -2 -6 <em>(</em><em>-</em><em>6</em><em> </em><em>on both</em><em> </em><em>sides</em><em>)</em>

c= -8

Thus, the equation of the perpendicular bisector is y= -2x -8.

5 0
3 years ago
Please help me, i will mark brainliest
user100 [1]

Answer:

B, C, E

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the definition of a prime factor?
Vlada [557]

Answer:

In other words: any of the prime numbers that can be multiplied to give the original number. ... Example: The prime factors of 15 are 3 and 5 (because 3×5=15, and 3 and 5 are prime numbers).

8 0
3 years ago
Read 2 more answers
1. (4x2 – 2x+8)+(x² + 3x - 2)
krek1111 [17]

Answer:

I   simplify  it and got 5x^2+z+6

Step-by-step explanation:

(4x2 – 2x+8)+(x² + 3x - 2)v=5x^2+z+6

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which angle has a tangent and cosine that are both negative? a. 110° b. 180° c. 210° d. 340°
    15·1 answer
  • Jerry has 8/9 gallon of paint. He uses 3/4 of it to paint his treehouse. How much paint is left?
    5·1 answer
  • Which statements are true?
    8·2 answers
  • What is the perimeter of the triangle?
    15·2 answers
  • Dr. Trebeck is testing adults to determine the effects of music tempo on how quickly they respond in a Jeopardy-style task. The
    14·2 answers
  • For which distributions is the median the best measure of center?
    14·2 answers
  • Can you solve this equation???
    5·1 answer
  • In the diagram, line l and line m are parallel lines cut by transversal n.
    11·1 answer
  • Zeke's motorcycle tire has a diameter of 20 inches. What is the tire's radius?
    11·1 answer
  • 1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!