(

)we need 3 equations
1. midpoint equation which is  (

) when you have 2 points
2. distance formula which is D= 

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height
so
x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(

) 
midpoint=(

)
midpoint= (15,8)
point x=(15,8)
y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(

)
midpoint=(

)
midpoint=(13,4)
Y=(13,4)
legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= 

D= 

D= 

D= 

D= 

BC=

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= 

D= 

D= 

D= 

D= 

XY=

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=

 and XY=

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= 

D= 

D= 

D= 

D= 

AD=

so we have
AD=

BC=
 
  XY=

AD and BC are base1 and base 2
XY=height
so 
(b1+b2) times 1/2 times height
(

) times 1/2 times 

 =
(

) times \sqrt{5} [/tex] = 

=

=80 

=252.982
X=(15,8)
Y=(13,4)
BC=

XY=

Area=80 

 square unit or 252.982 square units
 
        
        
        
Answer:
x^2 + 3x - 4
Step-by-step explanation:
solved using long division
 
        
             
        
        
        
F/g(x) = (2x^2 + 5x - 1)/(x + 3)
f/g(4) = (2(16) + 5(4) -1)/(4 + 3)
         = (32 + 20 -1)/7
         = 51/7
        
             
        
        
        
The last one is correct answer
        
             
        
        
        
Answer:
4/3
Step-by-step explanation: