Answer:
After 10 years, the population of the town will be of 5905.
After 50 years, the population of the town will be of 11487.
Step-by-step explanation:
The population of the town after x years is given by the following equation:
![P(x) = 5000(1.181)^{0.1x}](https://tex.z-dn.net/?f=P%28x%29%20%3D%205000%281.181%29%5E%7B0.1x%7D)
After 10 years, the population of the town will be of:
This is P(10). So
![P(10) = 5000(1.181)^{0.1*10} = 5000(1.181)^1 = 5905](https://tex.z-dn.net/?f=P%2810%29%20%3D%205000%281.181%29%5E%7B0.1%2A10%7D%20%3D%205000%281.181%29%5E1%20%3D%205905)
After 10 years, the population of the town will be of 5905.
After 50 years, the population of the town will be of:
This is P(50). So
![P(50) = 5000(1.181)^{0.1*50} = 5000(1.181)^5 = 11487](https://tex.z-dn.net/?f=P%2850%29%20%3D%205000%281.181%29%5E%7B0.1%2A50%7D%20%3D%205000%281.181%29%5E5%20%3D%2011487)
After 50 years, the population of the town will be of 11487.
Answer:
A
Step-by-step explanation:
F(9) = 18-9-(9)^2
=> f(9) = 18-91-81
=> f(9) = -153
= because if they are in the same distance,thede be =.
Answer:
P(Green ball) = 1/3
Step-by-step explanation:
You have a sack of 90 balls. 35 blue, 30 green and 25 pink. If you randomly pull one ball out of the bag, what is the probability of pulling a green ball?
The Probability of pulling a green ball =
P(Green ball) =
Number of green balls/ Total number of balls
= 30 green balls/90 balls
P(Green ball) = 1/3