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slamgirl [31]
2 years ago
12

Find by means of a vector( quantity) diagram . The resultant of two forces of 7 newton and 3 newton acting at right angle to one

another​
Mathematics
2 answers:
8090 [49]2 years ago
5 0

Answer:

The resultant of two forces of 7N and 3N acting at a right angle to one another is √58 N.

Step-by-step explanation:

Let the magnitude of the force of 7N be denoted as “F₁” on the x-axis and the magnitude of the force of 3N be denoted as “F₂” on the y-axis.

We are given that the two forces make an angle of 90° to one another as shown in the figure attached below.

Also, in the figure, we can see that the resultant force is denoted as “F”.

Now,  

The magnitude of the resultant force can be calculated by using the Pythagoras theorem,  

 

∴ F = √[F₁² + F₂²]

⇒ F = √[7² + 3²]

⇒ F = √[49 + 9]

⇒ F = √[58] N

OLga [1]2 years ago
4 0

Answer:

h. . . .. . .

. . . . . . . . . . . . . .. .

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Answer:

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Step-by-step explanation:

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3 years ago
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tensa zangetsu [6.8K]
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8 0
3 years ago
Read 2 more answers
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

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C)

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To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

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P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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Answer:

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