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3 years ago

PLEASE HELP!! DESPERATE!

Mathematics

1 answer:

avanturin [10]3 years ago

7 0

Answer:

Lenght: 34.51 mm

Area: 1035.33 mm^2

Step-by-step explanation:

let x be the unknown sidelength

tan(41) = 30/x

x = 34.51

multiply by 30 to get area

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Solve the following <br><br><br> C^2-14=5c

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Answer:

c = - 2, c = 7

Step-by-step explanation:

Given

c² - 14 = 5c ( subtract 5c from both sides )

c² - 5c - 14 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the c- term (- 5)

The factors are - 7 and + 2, since

- 7 × 2 = - 14 and - 7 + 2 = - 5, hence

(c - 7)(c + 2) = 0

Equate each factor to zero and solve for c

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The human lung has about 80 million alveoli. Give two features of the alveoli that allow large amounts of oxygen to enter the bl

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In Pennsylvania the average IQ score is 101.5 The variable is normally distributed and the population standard deviation is know

elena-14-01-66 [18.8K]

Answer:

P-value = 0.0368

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 101.5

Sample mean, $\bar{x}$ = 106.4

Sample size, n = 30

Alpha, α = 0.05

Population standard deviation, σ = 15

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 101.5\\H_A: \mu> 101.5$

We use One-tailed(right) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{106.4 - 101.5}{\frac{15}{\sqrt{30}} } = 1.789$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, students in Pennsylvania have an IQ that is significantly greater than the state average.

P-value can be calculated with the standard normal table.

P-value = 0.0368

P-value is lower than the significance level.

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