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3 years ago

Emergency plz help me !!

Mathematics

1 answer:

Vlad [161]3 years ago

6 0

Oh boyy--

The slope intercept form is : y= 5x+17

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If 4 liters equals 1 gallon then how many liters are in15.9 gallon of diluting agent?

svet-max [94.6K]

Answer:

63.6 liters

Step-by-step explanation:

1 gallon = 4 liters

15.9 gallons = ? liters

To find the number of liters, multiply 4 by 15.9.

15.9 gallons = 63.6 liters

If this anser is correct, please make me Brainliest!

4 0

3 years ago

2(x-+2)+4=6x-4(-1+x)

sertanlavr [38]

2x-4+4=6x+4-4x

2x=2x+4

c there is no solution

8 0

3 years ago

Read 2 more answers

Help! Please!

fomenos

Answer:

is the board game to BOARD for Neal so you have 1.54

Step-by-step explanation:

its ligit 5.5

6 0

3 years ago

Suppose the function f(x) = 2x + 12

yarga [219]

First figure out how much it costs to rent seven movies a month. f(7)=2(7) + 12–> 14 + 12–> $26 Now we need to find the difference between 26 and 10. 26 - 10= 16. So Casey needs $16 more to rent 7 movies a month

5 0

4 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago