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2 years ago

2. Mr. Walters starts preparing breakfast at

2 answers:

8 0

Answer: 55 minutes

Explanation:

Round 6:45 to 6:50.
From 6:50 it takes 1 hour/60 minutes to become 7:50.
Then subtract the 5 minutes we added when we rounded up to 6:50.
60-5=55 minutes

castortr0y [4]2 years ago

4 0

65 minutes

Between 6:45 and 7:00, there are 15 minutes.

Between 7:00 and 7:50, there are 50 minutes.

15 minutes + 50 minutes = 65 minutes or an hour and 5 minutes

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The value of s for a relationship between number of seconds, x, and number of jumping jacks of an athlete, y, is calculated as 3

melamori03 [73]

Answer:

its B

Step-by-step explanation:

your welcome

5 0

1 year ago

A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?

GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

$240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)$

$480=\left(2x+1\right)\left(6x-3\right)$

$480=12x^2-3$

Subtract 480 from both sides

$12x^2-3-480=480-480$

$12x^2-483=0$

$3\left(4x^2-161\right)=0$

$3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0$

solving

$2x+\sqrt{161}=0$

$2x=-\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{-\sqrt{161}}{2}$

$x=-\frac{\sqrt{161}}{2}$

also solving

$2x-\sqrt{161}=0$

$2x=\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{\sqrt{161}}{2}$

$x=\frac{\sqrt{161}}{2}$

Therefore, the values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

3 0

3 years ago

Robert is lying on the ground, looking at the top of a flagpole. The angle of elevation to the top of the flagpole is

NeTakaya

Answer:

Height of flagpole = 571 ft

Step-by-step explanation:

Given:

Angle of elevation to the top of the flagpole is 55° .

Distance from the eyes to the base of flagpole = 400 ft.

To find the height of the flagpole.

Solution:

We can draw the situation as a right triangle as shown below.

In triangle ABC.

$BC=400\ ft$

∠C= 55°

To find the length AB (height of the flagpole).

Applying trigonometric ratio :

$\tan\theta=\frac{Opposite\ side}{Adjacent\ side}$

$\tan C=\frac{AB}{BC}$

Plugging in values.

$\tan 55\°=\frac{AB}{400}$

Multiplying both sides by 400.

$400\tan 55\°=\frac{AB}{400}\times 400$

$571.26=AB$

∴ $AB\approx 571\ ft$

Height of flagpole = 571 ft

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3 years ago

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yanalaym [24]

Step-by-step explanation:

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3 years ago

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bearhunter [10]

Step-by-step explanation:

The only way the answer could be E is if the x² term under the radical is supposed to be t².

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f'(x) = √((2x)² − 2x) (2)

f'(x) = 2√(4x² − 2x)

f'(2) = 2√(4(2)² − 2(2))

f'(2) = 2√12

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3 years ago