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ludmilkaskok [199]
3 years ago
14

Im to tierd to post this

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

keep trying until you succeed :)

Step-by-step explanation:

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The weight of tigers follow a normal distribution with a mean of 220 kg and a SD of 30 kg. 1) If we randomly select a tiger, wha
mylen [45]

Answer:

0.89736

Step-by-step explanation:

We solve this question using z score formula

Z score = x - μ/σ

x = raw score

μ = population mean

σ = population standard deviation

Hence,

x = 258, μ = 220, σ = 30

Z = 258 - 220/30

=1.26667

Probability value from Z-Table:

P(x<258) = 0.89736

Therefore, the probability that his weights is less than 258 kg is 0.89736

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3 years ago
James has been assigned to provide candy for a class party he needs 5.3 pounds if candy cost $4.25 per pound at Harolds candy st
RoseWind [281]

Answer:

5.3 * 4.25 = 22.525

22.525 is about 22.5

so the answer is $22.50

3 0
2 years ago
John is creating crafts that require 4 2/5 inches of string each. If the string comes in a 50ft spool, how many items can he mak
Serggg [28]

Answer:

Step-by-step explanation:

7 0
3 years ago
What are the solutions to the quadratic equation (5y + 6)2 = 24?
Ivenika [448]

Answer:

y = \frac{2\sqrt{6} }{5} -\frac{6}{5}  OR  y = \frac{-2\sqrt{6} }{5} -\frac{6}{5}

Step-by-step explanation:

Our quadratic equation is: (5y + 6)² = 24.

The first step is to square root both sides:

5y + 6 = ±√24 = ±2√6

Now subtract 6 from both sides:

5y = ±2√6 - 6

Finally divide by 5 from both sides:

y = \frac{2\sqrt{6} }{5} -\frac{6}{5}  OR  y = \frac{-2\sqrt{6} }{5} -\frac{6}{5}

And, those are the solutions to the equation.

7 0
3 years ago
Read 2 more answers
Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}? A. the
Gwar [14]
B. The median of the data set

**Update; A. The lower quartile**
See other answer for explanation. 
8 0
3 years ago
Read 2 more answers
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