Answer: If the wall is 300 meters long, the dimensions of the fence with the maximum area will be 300 × 150 = 45000 m²
Step-by-step explanation:
try combinations in a chart
190 × (600-190)/2 = 38950 = 190 × 205 increasing area
200 × (600-200)/2 = 40000 = 200 × 200
220 × (600-220)/2 = 41800 == 220 × 190
240 × (600-240)/2 = 43200 == 240 × 180
260 × (600-260)/2 = 44200 == 260 × 170
280 × (600-280)/2 = 44800 . == 280 × 160
<u>300 × (600-300)/2 = 45000 == 300 × 150</u> Maximum Area
310 × (600-310)/2 = 44950 . == 310 × 145 decreasing area
320 × (600-320)/2 = 44800 . == 320 × 140
Answer:
i think its -5
Step-by-step explanation:
if you devide 25 by -5 you get -5
<u>Given</u>:
Let A denote the angle of the given triangle which measures ∠A = 81°
Let B denote the angle which measures ∠B = 40°
The length of the side a = x.
The length of the side b = 7 cm.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the law of sine formula.
Applying the law of sine, we have;
Substituting the values, we have;
Simplifying, we get;
Cross multiplying, we have;
Thus, the length of the side x is 10.8 cm.
Answer:
try b
Step-by-step explanation:
After 300 miles.
35+0.1x= 25+0.15x
<u> -0.1x -.01x</u> (0.1- 0.1 crosses out)
35= 25+0.15x
<u> -25 -25 </u> (25- 25 crosses out)
15= 0.15x
15/0.15= 0.15x/0.15 (crosses out)
300= x
