Answer:
Number of quarters → 15
Number of dimes → 2
Step-by-step explanation:
Let the number of dimes I have = y
And number of quarters = x
Since, I have amount in my pocket = $2
Therefore, 0.10y + 0.25x = 2
100(0.10y + 0.25x) = 100×2
25x + 10y = 200
5x + 2y = 40
2y = -5x + 40
y = -2.5x + 20 ---------(1)
Total number of coins in my pocket = 17
x + y = 17
y = -x + 17 ---------(2)
By using a graphing calculator we can graph these two lines (As attached)
Solution of the given system of equations will be the point of intersection of these lines.
Solution → (2, 15)
Number of quarters → 15
Number of dimes → 2
Answer: You are right it is 6
Step-by-step Explanation
Every circle counts as one so it is 6
BTW how do you make the picture appear
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
Answer:
Step-by-step explanation:
The foci are horizontally aligned.
horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
center (h,k)
vertices (h±a,k)
length of minor axis = 2b
foci (h±c,k), c² = a²-b²
Apply your data and solve for h, k, a, and b.
foci (±3√19, 6)
h = 0
k = 6
Length of minor axis = 2b = 10
b = 5
foci (h±3√19, 6)
c = 3√19
c³ = a² - b²
171 = a² - 25
a² = 196
x²/196 + (y-6)²/25 = 1
B-3/88 because the square trot of 67 is 3
