The answer is 294 i know cause i just took it
Answer:
The phrase is negative because you're moving backwards
Answer:
y = 2x - 2
Step-by-step explanation:
y= mx+b
m= slope
b= y-intercept (point on line where x= 0.... or the point where the line hits the y-axis)
Determine slope by using slope formula or by counting boxes
By counting boxes, you can see that each point is 2 units up, 1 unit right (2/1)
the slope is 2
the point where the line is touching the y-axis is (0, -2)
m = slope = 2
b = y-intercept = -2
y = 2x + (-2) OR y = 2x -2
Answer:
38
Step-by-step explanation:
Notice that the first triangle is an isosceles triangle, meaning that the base angles are equivalent. Since one angle is 62, we know that the other is 62 as well, which makes 124. This means that angle 2 is 56 degrees. Since 2 and 3 are on the same 'line', they both add up to 180. If 2 is 56, then angle 3 is 124. So the three angles inside the triangle are 124, 18, and x. So, 124+18=142. 180-142= 38
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to
