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2 years ago

NO LINKS!!!!!

Mathematics

1 answer:

8090 [49]2 years ago

6 0

9514 1404 393

Answer:

5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is ...

b^2 -4ac

so the discriminant of your equation is ...

10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

100 +4ac = 0

25 +ac = 0

ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

Additional comment

Your problem statement does not require that 'a' be non-zero. If a=0, then the equation will have one real solution for any value of c.

If you restrict the solutions to integers, then possibilities include ...

(a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

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5 0

3 years ago

9 POINTS!!!

denpristay [2]

14.49.

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3 years ago

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 3 small boxes has a t

faltersainse [42]

Answer:

one large box equals 15.75kg

one small box equals 13.75kg

Step-by-step explanation:

First, identify your variables:

Let "l" represent the weight of one large box.

Let"s" represent the weight of one small box.

Then, stack the two equations on top of each other:

$5l+3s=120\\7l+9s=234$

Next, multiply the first equation by 3 so we can use elimination of the "s" variable to find the "l" variable first:

$3(5l+3s=120)\\7l+9s=234\\\\15l+9s=360\\7l+9s=234$

Now, subtract the two equations to cancel out the s-variable and find the l-variable:

$15l+9s=360\\-(7l+9s=234)\\8l=126\\\frac{8l}{8}=\frac{126}{8}\\l=15.75$

Then, substitute your l-variable in the original first equation to find the s-variable:

$5l+3s=120\\5(15.75)+3s=120\\78.75+3s=120\\78.85-78.75+3s=120-78.75\\3s=41.25\\\frac{3s}{3}=\frac{41.25}{3}\\s=13.75$

With all the information that is collected, you find that one large box weighs 15.75kg and one small box weighs 13.75kg.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

Took the quiz hope this helps :)

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3 years ago