Yesterday, the store made $10,500 in sales
Given:
Payee: Vanderbilt Corporation
Notes Receivable from Stanford Company
<span>$12,000, 7%, 8-month
Debit Credit
October 1, 2016
Notes Receivable 12,000
Cash 12,000
*to record notes receivable from Stanford Company
December 31, 2016
Interest Receivable 560
Interest Income 560
12,000 * 7% * 8/12 = 560
*to recognize interest earned but not yet received
June 1, 2017
Cash 12,560
Notes Receivable 12,000
Interest Receivable 560
*to recognize full payment on note.</span>
You would need 3 pails of plaster, specifically about 2 pails and a fifth of another but you cant buy a fraction of a pail, so 3 pails are needed.
Answer:
B: 12/25
Step-by-step explanation:
You have the correct answer marked. This is correct because the probability of grabbing a purple marble is 24/50 which if we divide by 2 to simplify is 12/25.
Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ±
* (S/√n)

6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!