From what we know, p is 20 more than q. So, we can assume p = 20 + q. Q can also be found by subtracting 20 from both sides. So, q = p - 20.
Hope this helped!
It should be the number 55. <span> ❤</span>please mark me as brainliest ❤
Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
Answer:
28
Step-by-step explanation:
g(10)=3n-2
10=n
3(10)-2
REMEMBER PEMDAS
Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction.
3(10)=30
30-2=28
Hope this helps have a wonderful evening!
Answer: The greatest number of pages Kenji can decorate = 3
Step-by-step explanation:
Given: Total heart stickers = 15
Total star stickers =12
If all the papers identical, with the same combination of heart and star stickers and no stickers left over.
Then the greatest number of pages Kenji can decorate = GCD(15,12) [GCD=greatest common divisor]
Since 15 = 3 x 5
12=2 x 2 x 3
GCD(15,12) =3
Hence, the greatest number of pages Kenji can decorate = 3