Answer: 6x² + 36x + 22
Step-by-step explanation:2 faces (x + 3) by (x + 7), area of both these faces 2(x+3)*(x + 7)
2 faces (x + 3) by (x - 1), area of both these faces 2(x+3)*(x - 1)
2 faces (x -1 ) by (x + 7), area of both these faces 2(x-1)*(x + 7)
Whole surface area is
2(x+3)*(x + 7) + 2(x+3)*(x - 1) + 2(x-1)*(x + 7) =
=2(x² + 3x +7x +21) + 2(x² +3x -x - 3) + 2(x² - x +7x -7)=
=2x² + 20x +42 + 2x² + 4x - 6 + 2x² + 12x -14 =
= 6x² + 36x + 22
Answer:
45 square meters
Step-by-step explanation:
we know that
The area of trapezoid is equal to
where
b1 and b2 are the parallel bases
h is the height of trapezoid (perpendicular distance between the parallel bases)
we have
substitute
Y=180-111=69
x=360-123-70-69=98
That's your answer.
Whole numbers are positive numbers without decimals. First, list all the whole number factors of 36:
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6
Next, see which one of those pairs has the highest sum:
1+36=37
2+18=20
3+12=15
4+9=13
6+6=12
The greatest possible sum the numbers can have is 37.
Hope this helps!!