Answer:
They are only equal on day 0, both having 10 population.
Step-by-step explanation:
Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

Given the bacteria on the stove is measured at 10 and doubles every 4 days we can create another equation:

To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

Divide both sides by 10

Since both exponents have the same base we can set the exponents equal to eachother and solve for x:

Multiply both sides by 3 to isolate x on the left side

Multiply both sides by 4 to remove fraction

Subtract 3x to isolate x on the left side

Plug x into one of our original equations

Solve

V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
we know that
A difference of squares problem can be factored as follows:

in this problem we have

Applying difference of squares

the term

substitute

therefore
<u>the answer is</u>

-x-=+ negative times a negative is a positive