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lutik1710 [3]
2 years ago
12

Is the relationship =~ or 180 set up on equation and solver for x find the measure the gíren

Mathematics
1 answer:
larisa86 [58]2 years ago
8 0

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What is an equation of the line that passes through the points (-4,1) and (4,4)?
Ray Of Light [21]

Answer:

y = \frac{3}{8} x +  \frac{5}{2}

Step-by-step explanation:

☆Remember: m =  \frac{y_2 - y_1}{x_2 - x_1}

☆Remember: Slope-intercept form -> y = mx + b

☆Now. We first need to find the slope.

m =  \frac{4 - 1}{4 -  (- 4)}  =  \frac{3}{8}

☆Now the y-intercept.

y =  mx + b \\  \\ 4 =  \frac{3}{8} (4) + b \\  \\ 4 =  \frac{3}{2}  + b \\   \frac{ -  \frac{ 3}{  2} =  -  \frac{ 3}{ 2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  }{ \frac{5}{2} = b }

8 0
3 years ago
Evaluate the factorial expression. 24!/21!
Burka [1]

Answer:

12144.

Step-by-step explanation:

(self-explanatory)

I hope this helped, have a nice day.

6 0
3 years ago
What is the range of y=sec^-1(x)?
Bingel [31]
Assuming that the x is not part of the ^-1 the range would be 

[0,π/2) U (π/2,<span>π]</span>
3 0
3 years ago
Read 2 more answers
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
A number decreased by the sum of the number and four<br> and please show the steps
FromTheMoon [43]

let the number be x.

a number decreased means

x-

and the sum of the number and 4 is

x+4

to put the expression together, we get. put them in parentheses

x - ( x+4 )

= x - x -4

= - 4

3 0
3 years ago
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