Answer:
x = - 1/6 + √-119/6, and, - 1/6 - √-119/6
Step-by-step explanation:
Using the quadratic formula which is: - b ± √b² - 4ac / 2a
a = 3, b = 1, c = 10
- 1 ± √1² -4 * 3 * 10 / 2 * 3
- 1 ± √1 - 120 / 6
-1 ± √-119 / 6
= -1/6 + √119/6, or - 1/6 - √-119/6
Answer:
AB-C^2 = 3x^3 + x^2 + 9
Step-by-step explanation:
Hi
AB = (x^2)*(3x+2)= 3x^3 + 2x^2
C^2= (x-3)^2 = x^2 - 9
So
AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9
Y - 4.5 = 12.2
your solving for y which means your trying to get rid of 4.5 so that y can equal something. The opposite of -4.5 would be +4.5, so you would add 4.5 to both sides to get
y = 16.7
So your answer would be
A. Add 4.5
and also dont' say your stupid because all you need is a little explanation and you'll get it, its very easy you just need to take the time to practice :-)
You are describing where I live only that temperature is a bit low. I'm sorry to say it is neither one.
t_daily = t_average +/- 5
The highest temperature would be
t_daily = t_average + 5
t_daily = 1 + 5
t_daily = 6
================
The Lowest temperature would be
t_daily = t_average - 5
t_daily = 1 - 5
t_daily = - 4
Sounds about right for December.
