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lukranit [14]
3 years ago
14

What number is equivalent to 35/4? A. 8.34 B.8.75 C. 7 D. 31

Mathematics
2 answers:
Alex73 [517]3 years ago
5 0
Hello!

The answer is B!

Hope that helped!
OverLord2011 [107]3 years ago
3 0
The answer is B) 8.75If you use a calculator and divide 4 from 35 you will get that answer :)
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Is 100 in greater than 3yd 1ft
wolverine [178]
1 yard = 36 inches

3 * 36 = 108

1 foot = 12 inches

108 + 12 = 120

So 3 yards and 1 foot is equal to 120 inches.

120 is greater than 100 so 3 yards and 1 foot is greater than 100 inches.
3 0
3 years ago
Read 2 more answers
5. A study found that the average time it took a person to find their dream home was 5.9 months. If a sample of
solong [7]

Answer:

The 95% confidence interval of the mean time it took a person to find their dream home is between 5.64 months and 6.16 months.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{0.8}{\sqrt{36}} = 0.26

The lower end of the interval is the sample mean subtracted by M. So it is 5.9 - 0.26 = 5.64 months

The upper end of the interval is the sample mean added to M. So it is 5.9 + 0.26 = 6.16 months.

The 95% confidence interval of the mean time it took a person to find their dream home is between 5.64 months and 6.16 months.

4 0
3 years ago
Pls help asap!!!
wlad13 [49]

Answer:

negative 2.5

Step-by-step explanation:

It is belove sea level, so it will be between negative 2 and negative 3 on a vertical number line.

4 0
2 years ago
Show me how you solve it
julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n} }

Therefore:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  }

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{( {a}^{m} ) ^{n} =  {a}^{m \times n}  }

Thus:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  = {5}^{5 \times 4}   } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =   {5}^{20} }

7 0
2 years ago
Need help with this
svlad2 [7]
The answer to your question is C.
5 0
2 years ago
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