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kirill [66]
3 years ago
15

(a) 3 - 2/3÷4/3 × 7(b) [(2/3)/(5/6)]-2/5(c) {(-3/4) +( 1/2)}/{(2/5)-(5/2)}​

Mathematics
2 answers:
BartSMP [9]3 years ago
6 0

Step-by-step explanation:

a. (3 - 2/3) ÷ (4/3 x 7)

= [(3 x 3) / (1 x 3) - 2/3] ÷ 28/3

= (9/3 - 2/3) ÷ 28/3

= 7/3 x 3/28

= 21/84

= (21 x 1) / (21 x 4)

= 1/4

b. 2/3 ÷ 5/6 - 2/5

= 2/3 x 6/5 - 2/5

= 12/15 - 2/5

= (3 x 4) / (3 x 5) - 2/5

= 4/5 - 2/5

= 2/5

c. (- 3/4 + 1/2) ÷ (2/5 - 5/2)

= [- 3/4 + (1 x 12) / (2 x 2)] ÷ [(2 x 2) / (5 x 2) - (5 x 5) / (2 x 5)]

= (- 3/4 + 12/4) ÷ (4/10 - 25/10)

= 9/4 ÷ (- 21/10)

= 9/4 x - 10/21

= - 90/84

= (6 x - 15) / (6 x 14)

= - 15/14.

If you have any doubt, then you can ask me in the comments.

Semmy [17]3 years ago
4 0

Answer:

a = -1/2      b = 2/5     c = -2

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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago
Justin took a quiz with five multiple choice (A-D) and five true/false questions. How many different ways can he answer the ques
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Answer:

32,768 ways

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True/ false questions = 5 ; number of options = 2 (True or false)

Ways of answering = 2^5 = (2 * 2 * 2 * 2 * 2) = 32

Number of Multiple choice questions = 5

Number of options (A - D) = 4 options

Ways of answering = 4^5 = (4 * 4 * 4 * 4 * 4) = 1024

32 * 1024 = 32,768 ways

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