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3 years ago

Which graph shows a line with a slope of 3?

Mathematics

1 answer:

ANTONII [103]3 years ago

4 0

Answer:

The first graph shows a slope of 3.

Step-by-step explanation:

If the slope is 3, it's actually 3/1 because of rise/run. So you find any point on the graph that's directly between two lines, like (-1,-5). Since the line is positive, you would go right one and up three. Then you see if that point is directly between two lines. The next point is (0, -2). If you did the same on the second graph, it wouldn't match up.

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For the function f(x) = 2x +3, evaluate f(3).

AveGali [126]

Answer:

Step-by-step explanation:

f(3) = 2(3) + 3

= 9

4 0

3 years ago

Read 2 more answers

A rectangular quilt is 5 feet wide and 7 feet long. How many feet of lace are needed to cover the edges of the quilt?

miv72 [106K]

P = 2L + 2W
L = 7
W = 5
P= ???
P = 2*7 + 2*5
P = 14 + 10
P = 24 feet of lace.

6 0

3 years ago

Read 2 more answers

“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

Please, help im being timed !!!

Agata [3.3K]

B (2x+5y=-10) is the answer.

3 0

2 years ago

when Jeremy surveyed Thirty seventh grade students at the community pool he found that to a 15 had not read at least one book du

Anettt [7]

200 * 2/15 = the number of students that didn't read any books. This is 26.6, so 40 is not a good estimate 40 students is 20 percent versus 26 being approximately 13 percent.

hope this helps i tryed

ur welcome(;

have a great day

8 0

2 years ago