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Anna [14]
3 years ago
15

Which graph shows a line with a slope of 3?

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

The first graph shows a slope of 3.

Step-by-step explanation:

If the slope is 3, it's actually 3/1 because of rise/run. So you find any point on the graph that's directly between two lines, like (-1,-5). Since the line is positive, you would go right one and up three. Then you see if that point is directly between two lines. The next point is (0, -2). If you did the same on the second graph, it wouldn't match up.

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Need help ASAP thank you
Sedaia [141]

The height of the barrel is 6 feet.

3 0
3 years ago
7
elixir [45]

The area of the track will be 78501 m². The area of the track is equal to the area of the circle.

<h3>What is the area?</h3>

The space filled by a flat form or the surface of an item is known as the area.

The number of unit squares that cover the surface of a closed-form is the figure's area. Square meters and other similar units are used to measure area.

The area of the track is found as;

\rm A=\frac{\pi}{4} d^2 \\\\ \rm A=\frac{3.14}{4} (100)^2 \\\\ A=7850 \ m^2

Hence, the area of the track will be 78501 m².

To learn more about the area, refer to the link;

brainly.com/question/11952845

#SPJ1

8 0
2 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
Bab needs help please!
schepotkina [342]
Answer: it's 3.14 in^3
6 0
2 years ago
Read 2 more answers
Anyone tell me the answer quick it is my homework
WITCHER [35]

Answer:

a. 8/24

divide denominator and numenator by three

1:3

b. 16/24

2:3

6 0
3 years ago
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