The longest length you can get with no extra is 56cm
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
Step-by-step explanation:
Given the rational expression: 
, to express this in simplified form, we would need to apply the concept of partial fraction.
Step 1: factorise the denominator
Thus, we now have: 
Step 2: Apply the concept of Partial Fraction
Let,
= 
Multiply both sides by (x - 1)(x - 4)
= 
Step 3:
Substituting x = 4 in
Substituting x = 1 in
Step 4: Plug in the values of A and B into the original equation in step 2
Answer:
F = $11,421.90
Final value after 5 years F = $11,421.90
Complete question;
You purchased a vehicle for $32,000. It's value will depreciate at a rate of 18.62%. What will it's value be in 5 years, when you finally have it paid off
Step-by-step explanation:
Given;
Initial value P = $32,000
Depreciation rate r = 18.62% = 0.1862
Time t = 5
Final value = F
Using the compound depreciation formula;
F = P(1 - r)^t
Substituting the values;
F = $32,000(1 - 0.1862)^5
F = $11,421.90
Final value F = $11,421.90
V = πr²h
V = (3.14)(5)²(16)
V = (3.14)(25)(16)
V = 1256
Hope this helps :)
