First question: Answer is D
∵ Area of rectangle is L ⋅ W = 12 ⋅ 6 = 72 
∵ Area of the shaded region is 36 
∴ The area of the unshaded region =
the area of the whole rectangle - the shaded region =
72 - 36 = 36 
∴ The area of the unshaded region = 36 
Second question: Answer is A
∵ Area of triangle is
Bh =
⋅ x ⋅ 4 = 32
∵ Height (h) = 4 ft
∴ Base (B) =
⋅ 2 = 8 ⋅ 2 = 16
∴ Base (B) = 16 ft
Third question: Answer is D
6.009 = 6 + 0.009
Fourth question: Answer is B
104.0032 = One hundred four and thirty-two ten-thousandths
Fifth question: Answer is B
∵ Perimeter of rectangle = 2(W+L) =
2(80+120) = 2 ⋅ 80 + 2 ⋅ 120 = 160 + 240 = 400 
∴ He needs 400
of fencing
The first one in x _> 12
The second one is x<24
Good luck!
Answer: You add up all the terms given of EACH angle, and make this an addition problem that is "equal to 180" ; since all triangles have three angles that add up to 180 degrees. Then you solve for "x".
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(as follows) ; to get: " x = 29 ⅔ ° " .
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3x + 4 + 2x + x + 8 = 180 ;
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Combine the "like terms" ;
3x + 2x + x = 6x ;
4 + 8 = 12
So, we have: 6x + 12 = 180 ;
Now, subtract "12" from each side of the equation:
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6x + 12 − 12 = 180 <span>− 12 ;
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to get:
6x = 178 ;
Now, divide EACH SIDE of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ;
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6x / 6 = 178 / 6 ;
to get: x = 178/6 = 29 ⅔ ° .
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x = 29 ⅔ ° .
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Answer:
length of one leg of the triangle is 64 cm.
Step-by-step explanation:
Given : The hypotenuse of a 45°-45°-90° triangle measures 128 cm.
To find : What is the length of one leg of the triangle.
Solution : We have given that hypotenuse of a 45°-45°-90° triangle measures 128 cm.
By the 45°-45°-90° triangle rule ,
Perpendicular sides (legs) are equal .
Hypotenuse = √2 × either perpendicular side ( leg ).
128 = √2 × leg .
We can write 128 as 64 √2 and substitute in above
64√2 = √2 leg.
On dividing by √2 both sides and switching sides.
leg = 64 cm .
Therefore, length of one leg of the triangle is 64 cm.
Eazy 44,756
then you do 167 not take 447 the first part of the first number now can 167 go into 447 yes it can then from there wants you have leftover numbers then add 5 to the leftover and see if 167 can go into it from there take the last digit from 44,756 and there you go