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IgorC [24]
3 years ago
9

Find the average rate of change of k(x) = x' over the interval [3, 9].

Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer:

y=6x×2/4

x=7

thanks for the points

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Bobby think that 5^2 = 10. What is wrong with this answer
Korvikt [17]

Answer:

see below

Step-by-step explanation:

5^2  means 5*5  not 5*2

5^2 = 5*5 = 25  not 10

5 0
3 years ago
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The population of rabbits in an area can be modeled with an exponential function. In the first count, there are 250 rabbits. One
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The answer will be definitely be A don’t listen
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Log4 x + log4 (x – 3) = 1 Solve the equation.
Natasha_Volkova [10]

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x is EQUIVALENT to 2.89

Step-by-step explanation:

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3 years ago
Which ratio is equivalent to 9/36
balandron [24]

Answer:

1/4

Step-by-step explanation:

Step 1: Find the GCF. List out the factors of the numerator and the denominator. 1, 3, 9 are the factors of 9, while 1, 2, 3, 4, 6, 9, 12, 18, and 36 are the factors of 36. 9 is a common factor of both of them, so the GCF is 9.

Step 2: Divide the numerator and denominator by 9 (the GCF). 9/9 is 1. 36/9 is 4. This means that our fraction is 1/4. The fraction is in simplest form.

5 0
3 years ago
Read this E[2X^2 â€" Y].
djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.

If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:

E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]

Or, if you're given the expectation and variance of <em>X</em>, you have

Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²

→   E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]

Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.

6 0
3 years ago
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