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miskamm [114]
3 years ago
9

Use the properties of addition to simplify this expression. -8w + 5 + 9w -1

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0
The answer is w+4.
kyzylskhzkhzlgzy
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ATCs are required to undergo periodic random drug testing.
aleksandr82 [10.1K]

Answer:

The responsess to the given question can be defined as follows:

Step-by-step explanation:

P(medication\ used) = 0.007 \\\\P( drug \not\ used ) = 1 - 0.007 = 0.993\\\\P(test\ positive  | medication \ used) = 0.96 \\\\ P(test \ negative | medication \ used) = 1 - 0.96 = 0.04\\\\

P(Point | Non-used\ medication )=0.93\\\\ P(Point |No\ medication ) = 1 - 0.93 = 0.07

As per the given info we draw the tree diagram which is defined in the attachment file.

P ( test \ is\  positive ) = P( medication \ used ) \times P( Test \ positive | medication \ used ) + P( medication not \ used ) \times  P( Test\ positive | medication \ not \ used )

                  = ( 0.007 \times 0.96 ) + ( 0.993\times 0.07 )\\\\= 0.0762

P( medication \ used | test\ positive )= \frac{\textup{P( medication used ) *P( Test positive given medication  used )}}{\textup{P( medication used )}}  

= \frac{( 0.007\times 0.96 )}{0.0762}\\\\= 0.0882

8 0
3 years ago
What is the length of the hypotenuse?<br> A 55 ft<br> B 48 ft<br> C = ?<br> feet
oee [108]

I think hypotenuse is A 55 feet

7 0
2 years ago
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FromTheMoon [43]

Answer:

x = 40/21

Step-by-step explanation:

This should be the right answer...

5 0
3 years ago
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What is the simplified form of 4x plus 2 over x plus 5 minus the fraction 3x plus 1 over x plus 5?
viva [34]
We have that

[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
<span>They have common denominators, so just add the numerators like normal fractions:</span>
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)

the answer is
(x+1)/(x+5)
4 0
3 years ago
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Determine the length of a chord whose central angle is 150° in a circle with a radius of 223 centimeters. Question 12 options: 1
faltersainse [42]

Answer:

4) 430.8 centimiters

Step-by-step explanation:

3 0
3 years ago
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