Use the properties of addition to simplify this expression. -8w + 5 + 9w -1

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

jasmine has 8 seashells. three- quarters are clamshells. how many shells are clamshells 3/4=_/8 a)3 shells b)4 shells c) 6 shell

fgiga [73]

The answer for your question is 6/8

6 0

3 years ago

a man owned 75 shares of stock worth $50 each the corporation declared a dividend of 8% payable in stock how many shares did he

Arturiano [62]

Total number of shares owned is 75 shares
value of each share=$50
value of 50 shares will be:
75*50=$3750
the dividend earned
8/100×3750
=$300

Answer: $300

3 0

3 years ago

4. The distance covered by the cook in Triangle A equals _______________ eighteen-inch steps.

laiz [17]

We know that

to convert feet to inches we must multiply by 12

4. The distance covered by the cook in Triangle A equals
a) fridge and stove-----------> 5*16*12=960 in
b) fridge and sink-------------> 10*22*12=2640 in
c) sink and stove--------------> 15*16*12=2880 in
then add, 960 + 2640 + 2880 = 6480 in

the answer asks for the distance in 18 in lengths
so divide 6480 by 18 -------------> 6480/18=360

the answer part N 4) is 360 eighteen-inch steps

5. The distance covered by the cook in Triangle B equals
a) fridge and stove-----------> 5*16*12=960 in
b) fridge and sink-------------> 10*16*12=1920 in
c) sink and stove--------------> 15*16*12=2880 in
then add, 960 + 1920 + 2880 = 5760 in

the answer asks for the distance in 18 in lengths
so divide 5760 by 18 -------------> 5760/18=320

the answer part N 5) is 320 eighteen-inch steps

6. The distance covered by the cook in Triangle A equals
a) fridge and stove-----------> 5*15*12=900 in
b) fridge and sink-------------> 10*22*12=2640 in
c) sink and stove--------------> 15*15*12=2700 in
then add, 900 + 2640 + 2700 = 6240 in

the answer asks for the distance in 18 in lengths
so divide 6240 by 18 -------------> 6240/18=346.67------> 347

the answer part N 6) is 347 eighteen-inch steps

3 0

3 years ago

Hii my other account got banned and it sucks so now can I plz get a boy

Taya2010 [7]

... why would you say that on brainly....

5 0

3 years ago

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