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ss7ja [257]
3 years ago
7

Wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba

Mathematics
2 answers:
REY [17]3 years ago
8 0

Answer:

epic ninja

Step-by-step explanation:

ninja

Nostrana [21]3 years ago
6 0

Answer:

wooowooowowowowowowowowow

Step-by-step explanation:

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PLEASE HELP!!!!!! ILL MAKE BRAINLIEST ​
lesya692 [45]

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x = 17

Step-by-step explanation:

75 = 4x + 7

68 = 4x

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6 0
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A liquid mixture of 56 ounces contains 14 ounces of sugar and the rest is water. What is the ratio of sugar to water
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70 ounces Madison myrick
7 0
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Does this graph represent a function? What is the domain and range of the graph?
eimsori [14]

Answer:

Yes; domain: all real numbers; range: y \geq 0

Step-by-step explanation:

1. Use the vertical line test to see if it is a function.

2. Figure out what the lowest and highest point x can be. In this case x can be any number

3. Figure out what the lowest and highest point of y can be. In this case y is not negative, the lowest it can be is 0. So y \geq 0

*Note: Domain are the x values & Range are the y values

4 0
4 years ago
Can someone help me out with this my grade are bad
Pavlova-9 [17]

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6.24 is the answer rounded to the nearest hundreth

3 0
3 years ago
The points at x equals=​_______ and xequals=​_______ are the inflection points on the normal curve
uysha [10]
We know that the probability density function of a variable that is normally distributed is f(x) = 1/(σ√2π) * exp[1/2 (x – µ). Its inflection point is the point where f"(x) = 0.
Taking the first derivative, we get f'(x) = –(x–µ)/(σ³/√2π) exp[–(x–µ)²/(2σ²)] = –(x–µ) f(x)/σ².
The second derivative would be f"(x) = [ –(x–µ) f(x)/σ]' = –f(x)/σ² – (x–µ) f'(x)/σ² = –f(x)/σ² + (x-µ)² f(x)/σ⁴.
Setting this expression equal to zero, we get
–f(x)/σ² + (x-µ)² f(x)/σ⁴ = 0
Multiply both sides by σ⁴/f(x):
–σ² + (x-µ)² = 0
(x-µ)² = σ²
x-µ= + – σ
x = µ +– σ
So the answers are x = µ – σ and x = µ + σ.






8 0
3 years ago
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