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ss7ja [257]
3 years ago
7

Wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba

Mathematics
2 answers:
REY [17]3 years ago
8 0

Answer:

epic ninja

Step-by-step explanation:

ninja

Nostrana [21]3 years ago
6 0

Answer:

wooowooowowowowowowowowow

Step-by-step explanation:

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On a parallelogram, the vector from one vertex to another vertex is (9,-2). What is the length of the side?
sertanlavr [38]

Answer:  Second Option is correct.

Step-by-step explanation:

Since we have given that

In a parallelogram, the vector from one vertex to another vertex is (9,-2)

So, the co-ordinate of first vertex will be (9,0).

And the coordinate of second vertex will be (0,-2).

As we know the formula for "Distance between two coordinates":

So, The length of the side is given by

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\Distance=\sqrt{(9-0)^2+(0-(-2))^2}\\\\Distance=\sqrt{9^2+2^2}\\\\Distance=\sqrt{81+4}\\\\Distance=\sqrt{85}

Hence, Second Option is correct.

6 0
3 years ago
Read 2 more answers
What is the verbal phrase for the following expression? 5n
erik [133]
The answer is A
Five times a number
6 0
3 years ago
Read 2 more answers
I need help community
Tamiku [17]

Answer:

Option C, F(x) = (x+2)/(x+1)

Answered by GAUTHMATH

3 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
A cylinder has a volume of 75 cubic centimeters. What is the volume of a sphere with the same height and radius?
bagirrra123 [75]
The sphere and the cylinder have the same heightbecause of this the height of the cylinder is equal to the diameter of the spherethe diameter of the sphere is 2*7=14 cm, so the height of the cylinder is also 14 cmthe radius of the cylinder is 7 cmV=∏*r^2*hV=3.14159*7^2*14V=3.14159*49*14V=3.14159*686V=2155.13074 cubic cm, or...V=(22/7)(7^2)(14)       (22/7 is an approximation for pi)V=(22/7)(49)(14)V=(22)(7)(14)V=(22)(98)V=2156 cubic cm
8 0
3 years ago
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