2, 67, and 83 are all prime. 63 and 91 are composite. For the bottom question the answer is A and B.
Answer: well its 25% i think because if you take them each one all chances are 25% bacause bur it would be 50%/50% because to are the same but the chances of pulling the not that sames ones would also be a 50/50
I REALLY DONT KNOW IF IM RIGHT SO IM SORRY IF NOT IM DUMB
Answer:
Im in high school to i did this freshman year but the third column the 90s would be noticeable outliers. If you go into google sheets you could easily find this out by putting the data in.
Step-by-step explanation:
Answer:
-4/11 or -0.36363
Step-by-step explanation:
;)
X = 5/6.
The square of 3x+1 is written as (3x+1)². The square of x-2 is (x-2)². Using the information given to us, we want to solve the equation
(3x+1)²=9(x-2)²
(3x+1)(3x+1)=9(x-2)(x-2)
Multiplying the first two binomials, we have:
3x*3x + 1*3x + 1*3x + 1*1 = 9(x-2)(x-2)
9x²+3x+3x+1 = 9(x-2)(x-2)
9x²+6x+1 = 9(x-2)(x-2)
Multiplying the second two binomials, we have:
9x²+6x+1 = 9(x*x-2*x-2*x-2(-2))
9x²+6x+1 = 9(x²-2x-2x+4)
9x²+6x+1 = 9(x²-4x+4)
Using the distributive property gives us
9x²+6x+1 = 9*x²-9*4x+9*4
9x²+6x+1 = 9x²-36x+36
Subtracting 9x² from both sides leaves us
6x+1 = -36x + 36
Adding 36x to both sides we get
42x+1 = 36
Subtracting 1 from both sides we have
42x = 35
Divide both sides by 42:
42x/42 = 35/42
x = 35/42 = 5/6
