A sea lion jumped out of the water to a height of 3 feet above sea level. The number line shows the location of the sea lion at
the top of its jump. From this location, the sea lion dove down 9 feet. Describe how to use the number line to find the new location of the sea lion.
A. On the number line, move 9 units to the left. End at -6. The sea lion was 6 feet below sea level.
B. On the number line, move 9 units to the right. End at 12. The sea lion was 12 feet above sea level.
C. On the number line, move 9 units to the right. End at 6. The sea lion was 6 feet above sea level.
D. O3n the number line, move 9 units to the left. End at -12. The sea lion was 12 feet below sea level.
A. On the number line, move 9 units to the left. End at -6. The sea lion was 6 feet below sea level.
B. On the number line, move 9 units to the right. End at 12. The sea lion was 12 feet above sea level.
C. On the number line, move 9 units to the right. End at 6. The sea lion was 6 feet above sea level.
D. O3n the number line, move 9 units to the left. End at -12. The sea lion was 12 feet below sea level.
1 answer:
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Answer:
a) 0.1558
b) 0.7983
c) 0.1478
Step-by-step explanation:
If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em> and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:
(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?
(b) What is the probability that at least 4 arrive during a 1-hour period?
(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?
If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now
and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But
hence
P(X ≥ 75) = 1-0.852 = 0.1478