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weqwewe [10]
3 years ago
7

A cookie recipe that yields 48 cookies calls for 2 cups of flour a different cookie recipe that yields 60 cookies call for 3 cup

s of flour are these rates equivalent explain the reasoning
Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
No these rates are not equivalent. If you take 48 divides by 2 the result is 24. If you divide 3 into 60 the results is 20. Therefor not equivalent
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2 years ago
Translate the phrase into a math expression. Twelve more than the quotient of six divided by three. Responses (6÷3)+12 eft paren
aleksandr82 [10.1K]

The given phrase on translation to math expression is (6 ÷ 3) + 12 , the correct option is (a) .

In the question ,

an mathematical phrase is given , that is "Twelve more than the quotient of six divided by three" .

we have to translate it into mathematical expression ,

So , the term quotient of six divided by three is written as 6 ÷ 3 .

and phrase " more " is represented by " + " ,

Hence the given phrase,  "Twelve more than the quotient of six divided by three" is  (6 ÷ 3) + 12 .

Therefore , The given phrase on translation to math expression is (6 ÷ 3) + 12 , the correct option is (a) .

The given question is incomplete , the complete question is

Translate the phrase into a math expression , "Twelve more than the quotient of six divided by three" .

(a) (6÷3)+12

(b) 6÷(3+12)

(c) (3÷6)+12

(d) 3÷(6+12)

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5 0
1 year ago
In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
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