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3 years ago

15

Express the tan G as a fraction in simplest terms.

1 answer:

OLEGan [10]3 years ago

3 0

Answer:

$\frac{\sqrt{70} }{5}$

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What is the domain of the function?

denis23 [38]

Use a calculator it's not hard

6 0

4 years ago

Match each differential equation to a function which is a solution.

inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. $y = 3x+x^2$

$y' = 3 + 2x\\y'' = 2$

Replace in 1:

$y'' + y = 0$

$2 + 3x + x^2 \neq 0$

So, A is not an answer for 1

Replace in 2:

$y' = 3y$

$3+2x = 3(3x + x^2)$

So, A is not an answer for 2

Replace in 3

$2x^2y'' + 3xy'= y$

$2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2$

So, A is not an answer for 3

Replace in 4

$y'' + 6y' + 8y = 0$

$2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0$

So, A is not an answer for 4

B. $y = e^{-4x}$

$y' = -4e^{-4x}$

$y'' = 16e^{-4x}$

Replace in 1

$y'' + y = 0$

$16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0$

So, B is not an answer for 1

Replace in 2

$y' = 3y$

$-4e^{-4x} \neq 3e^{-4x}$

So, B is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq e^{-4x}$

So, B is not an answer for 3

Replace in 4

$y'' + 6y' +8y = 0$

$16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0$

So, B is an answer for 4

C. $y = sin(x)$

$y' = cos(x)$

$y'' = -sin(x)$

Replace in 1

$y'' + y = 0$

$-sin(x) + sin(x) = 0$

So, C is an answer for 1

We jump to

D. $y = x^{12}$

$y' = 12x^{11}$

$y'' = 132 x^{10}$

Replace in 2

$y' = 3y$

$12x^{11} \neq 3x^{12}$

So, D is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}$

So, D is not an answer for 3

E. $y = 6e^{3x}$

$y' = 18e^{3x}$

$y'' = 54e^{3x}$

Replace in 2

$y' = 3y$

$18e^{3x} = 3(6e^{3x}) = 18e^{3x}$

So, E is an answer for 2

3 0

3 years ago

If 64^-5 = 2^x, what is the value of x?

lapo4ka [179]

Answer:

lhsvlsblsbbkeblsvlsvlsvkahoelbevlevoe

8 0

3 years ago

Give the first five terms of the sequence <br> an=2n2+2

Eddi Din [679]

Answer:

The answer to your question is 3, 9, 19, 33, 51

Step-by-step explanation:

Sequence an = 2n² + 1

1st term a₁ = 2(1)² + 1 = 2(1) + 1 = 2 + 1 = 3

2nd term a₂ = 2(2)² + 1 = 2(2)² + 1 = 2(4) + 1 = 8 + 1 = 9

3rd term a₃ = 2(3)² + 1 = 2(3)² + 1 = 2(9) + 1 = 18 + 1 = 19

4rd term a₄ = 2(4)² + 1 = 2(4)² + 1 = 2(16) + 1 = 32 + 1 = 33

5th term a₅ = 2(5)² + 1 = 2(5)² + 1 = 2(25) + 1 = 50 + 1 = 51

4 0

4 years ago

Kim has 8 vanilla candles, 4 cherry candles and 6 raspberry candles. If he wants to choose 3 candles of different types, how man

aev [14]

8+4+6=18 so he has 18 choices

5 0

3 years ago