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UkoKoshka [18]
3 years ago
12

A 30 ft ladder leans against the side of a house. If the base of the ladder sits 10 ft away from the base of the house, what is

the ladder's angle of elevation?
Mathematics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

70.5°

Step-by-step explanation:

To solve for the ladder's angle of elevation, we solve using the Trigonometric function of Cosine

= cos θ = Adjacent/Hypotenuse

Where

Adjacent = Distance of the base from the house = 10ft

Hypotenuse = Length of the ladder = 30 ft

cos θ = 10/30

cos θ = 1/3

θ = arc cos 1/3

θ = 70.528779366

Approximately = 70.5°

Therefore, the ladder's angle of elevation is 70.5°

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Find the surface area of the cone with a diameter of centimeters and a slant height of millimeters
defon

Answer:

The first step in finding the surface area of a cone is to measure the radius of the circle part of. Therefore, the total surface area of the cone is 83.17cm2.

Step-by-step explanation:

5 0
3 years ago
Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
Help me with this answer I know there is no solution I just wanna know why
mylen [45]

Answer:

The solution x = 0 means that the value 0 satisfies the equation, so there is a solution. “No solution” means that there is no value, not even 0, which would satisfy the equation. ... This is because there is truly no solution—there are no values for x that will make the equation true

4 0
3 years ago
Read 2 more answers
Plspls help!!
zvonat [6]

a) the answer of the substitute is 300

b) the answer of the substitute is 7027/300 or 23.423

3 0
3 years ago
there is a room 7 feet x 9 feet you lay a 1-foot wide plank from corner to corner touching all 4 walls how long is the plank
Alex73 [517]

Answer:

Step-by-step explanation:

l^2=[(7-V2)/2]^2+(9-V2/2)^2=

49-7V2+2/4+81-9V2+2/4=

49+81+4/4-16V2=

131-16V2=108.4 ft

so l=V108.4≈10.4ft

5 0
3 years ago
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