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UkoKoshka [18]
3 years ago
12

A 30 ft ladder leans against the side of a house. If the base of the ladder sits 10 ft away from the base of the house, what is

the ladder's angle of elevation?
Mathematics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

70.5°

Step-by-step explanation:

To solve for the ladder's angle of elevation, we solve using the Trigonometric function of Cosine

= cos θ = Adjacent/Hypotenuse

Where

Adjacent = Distance of the base from the house = 10ft

Hypotenuse = Length of the ladder = 30 ft

cos θ = 10/30

cos θ = 1/3

θ = arc cos 1/3

θ = 70.528779366

Approximately = 70.5°

Therefore, the ladder's angle of elevation is 70.5°

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5.which of the following ordered pairs is a solution of the given system of linear equations
liq [111]

Answer:

the answer is d

Step-by-step explanation:

answers are shown

4 0
3 years ago
The scale of a map is 1cm:12 km. find the actual distance for 12cm
anzhelika [568]
This is simply a question about ratios. This ratio means that for every 1 cm on the map, there are 12 km in actuality. You can set this problem up in fractions:

1 cm           12 cm
--------   =   ----------
12 km             x

To solve for x, we cross-multiply, for the moment ignoring units. Remember, your answer will be in km.

1*x=12*12

x=144

If x=144, then for 12 cm, there are 144 km.


6 0
4 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
Please help as fast as you cannn
hodyreva [135]

Answer:

-43 < -35

(Negative 43 is less than negative 35).

8 0
3 years ago
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