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3 years ago

How do you simplify this expression- 16+(f+4)

Mathematics

1 answer:

Vinil7 [7]3 years ago

5 0

You take 16*f=16f then you take 16*4=64 so the awnser would be (16f+64)

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A 24000 gallon of pool is being filled at the rate of 40 gallons per minute at this rate how many minutes will it take to fill u

MA_775_DIABLO [31]

Answer:

Option no C 600 minutes

Step-by-step explanation:

Given:

gallons of pool = 24000 gallon

Rate at which it is filled = 40 gallons per minute

To find :

Time taken to fill the pool=?

Solution:

We know that rate is the time in which a thing is being done at per minute or per hour or per second. In our question it is given that the rate is 40 gallons per minute which means that 40 gallons are filled in one minute

Now

In one minute = 40 gallons filled

Total pool size = 24000 gallons

Total time taken = $\frac{Total pool size}{gallon filled in one minute}$

Putting in the values

Total time taken = $\frac{24000}{40}$

Total time taken = 600 minutes

So the answer is option c which is 600 minutes

4 0

3 years ago

560 divided by what equals 280

tangare [24]

560 divided by two equals 280

8 0

3 years ago

An artifact was found and tested for its carbon-14 content. If 72% of the original carbon-14 was still present, what is its prob

Artyom0805 [142]

Answer:

2700 years

Step-by-step explanation:

The exponential function for the fraction remaining is ...

r(t) = (1/2)^(t/5730)

where r is the remaining fraction and t is the time in years. We can solve for t to get ...

log(r) = (t/5730)log(1/2)

t = 5730·log(r)/log(1/2)

For the given r=0.72, the age of the artifact is estimated to be ...

t = 5730·log(0.72)/log(0.5) ≈ 2700 . . . years

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3 years ago

A roll of quarters is shaped like a cylinder and contains 40 quarters. Each quarter has a thickness of 1.75 mm and a diameter of

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3 years ago

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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second

faust18 [17]

$\bf \stackrel{\textit{Sam invested the first year}}{x} \qquad \qquad \stackrel{\textit{2nd year is \$2,000 less than \underline{x}}}{x-2000} \\\\\\ \stackrel{\textit{3rd year is \$1,000 more than \underline{x}}}{x+1000}\qquad \qquad \boxed{\stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}}\\\\ -------------------------------\\\\ \stackrel{\textit{Sally invested the first year \$1000 less than \underline{x}}}{x-1000}$

$\bf \stackrel{\textit{2nd year is \$1500 less than \underline{2x}}}{2x-15000}\qquad \qquad \stackrel{\textit{3rd year is \$1400 more than \underline{x}}}{x+1400} \\\\\\ \boxed{\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)}}$

$\bf \stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}=\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)} \\\\\\ 3x-1000=4x-1100\implies 100=x\impliedby \textit{Sam invested the first year} \\\\\\ \stackrel{\textit{Sally invested last year}}{x+1400}\implies 10+1400\implies 1500$

4 0

4 years ago