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Inessa [10]
3 years ago
14

Write an equation in slope-intercept form (y = mx + b).

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0

Answer:

x=1

Step-by-step explanation:

Anytime there is a vertical line, the y value becomes infinite as the line goes on forever. The only restriction on the line is on the x value of your coordinate. The same goes for a horizontal line, only the x value would become infinite and the y value would be constant.

Vertical Line: (x,∞)

Horizontal Line: (∞,y)

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HELPPPP MEEE PLEEASSEEEE !!!
Zarrin [17]

Answer:

67°

Step-by-step explanation:

Angle 67° and that at H are corresponding this are equal.

Therefore 67+46=113°

180-113=67 as the answer

6 0
3 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
9 months ago
What is the solution set for the equation x2-5x +6 =0
Liula [17]
You want to get the x's on one side and all the other numbers on the other side of the equation.
2x-5x+6=0
2x-5x=-6
-3x=-6
x=2
5 0
3 years ago
Read 2 more answers
The lengths of the sides of a triangle are in the ratio 3:4:5. Find the lengths of the sides of this triangle if its perimeter i
Strike441 [17]

Answer:  16 one side 32 second side 48 third side

Step-by-step explanation:

16;32;48

3;4;5

4 0
3 years ago
A) show that $n(2n + 1)(7n + 1)$ is divisible by 6 for all integers $n$.
goldenfox [79]
Hi,

A)
\dfrac{n(2n+1)(7n+1)}{6} \\

= \dfrac{14n^3+9n^2+n}{6} \\

= \dfrac{12n^3+6n^2}{6} + \dfrac{2n^3+3n^2+n}{6} \\

=2n^3+n^2+ \dfrac{n(2n^2+3n+1)}{6} \\

= 2n^3+n^2+ \dfrac{n(n+1)(2n+1)}{6} \\

= 2n^3+n^2+ 1^2+2^2+3^2+...+n^2\ is\ an\ integer.


B)
Only if n=4*k or n=4*k+1 , k beeing an integer.

8 0
3 years ago
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