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Reil [10]
3 years ago
14

True or false: This system of equations has no solution. y=2/12x+1 y=7/36x-2

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

false

Step-by-step explanation:

because there is no solution or answer

You might be interested in
The perimeter of a rectangular room is 60m.what is the width of the room if the length is 18m​
Angelina_Jolie [31]

Answer:

12

Step-by-step explanation:

18*2=36, 60-36=24, 24/2=12

3 0
3 years ago
Is the equation parallel perpendicular or neither ?<br><br> y = 5/4 x+1 and y = 5/4 x-7
weeeeeb [17]

Answer:

Parallel

Step-by-step explanation:

The equation of a line in slope - intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Both given equations are in this form, that is

y = \frac{5}{4} x + 1 → m = \frac{5}{4}

y = \frac{5}{4} x - 7 → m = \frac{5}{4}

Parallel lines have equal slopes thus the lines are parallel

4 0
3 years ago
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
3 years ago
Given that p²,q² are two roots of x²-x+16=0. <br>Form another equation with roots 1/p,1/q.
statuscvo [17]

Answer:

  x² -3/4x +1/4 = 0

Step-by-step explanation:

Consider the two equations in factored and expanded forms:

  (x -p²)(x -q²) = x² -(p²+q²)x +p²q² = 0   ⇒   p²+q² = 1, p²q² = 16

and

  (x -1/p)(x -1/q) = x² -(1/p+1/q)x +1/(pq) = 0

Consider the squares of the sum and product of roots:

  constant term: (1/(pq))² = 1/(p²q²) = 1/16   ⇒   1/(pq) = √(1/16) = 1/4

  x-term: (1/p +1/q)² = (p +q)²/(pq)² = (p² +q² +2pq)/(p²q²)

  = (p² +q²)/(p²q²) +2/(pq)

  = 1/16 +2/√16 = 9/16   ⇒   (1/p +1/q) = √(9/16) = 3/4

Then the equation with roots 1/p and 1/q is ...

  x² -3/4x +1/4 = 0

6 0
3 years ago
Solve the system by substitution. 4x=8y 2x+5y=27
MAVERICK [17]

Answer:

(6, 3)

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Alg I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define systems</u>

4x = 8y

2x + 5y = 27

<u>Step 2: Rewrite systems</u>

x = 2y

2x + 5y = 27

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Substitute:                         2(2y) + 5y = 27
  2. Multiply:                             4y + 5y = 27
  3. Combine like terms:          9y = 27
  4. Isolate <em>y</em>:                            y = 3

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Plug in y into an original equation to find x.</em>

  1. Substitute:               4x = 8(3)
  2. Multiply:                   4x = 24
  3. Isolate <em>x</em>:                  x = 6
3 0
3 years ago
Read 2 more answers
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