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elena-14-01-66 [18.8K]

3 years ago

8

Nathan plants equal sized squares of sod in his front yard. Each square has an area of 6 square feet.Nathan plants a total of 1,

000 squares in his yard.Whatis the total area of the squares of sod?

1 answer:

Neko [114]3 years ago

7 0

I THINK the answer is 6000 square feet because each one is 6 square feet and you have 1000 of them so 6 square feet times 1000 squares is 6000 square feet.

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The graph represents the fees in thousands of dollars, y, depending on the amount invested in millions, x, with one financial in

yanalaym [24]

Answer:

[0.20)

Step-by-step explanation:

I juss know stuff

7 0

3 years ago

Read 2 more answers

If the scale on a map is 1/4 in. = 50 miles, how many miles do 3 3/8 inches represent?

Korvikt [17]

Hey there Fish Girl!

So, if $\left[\begin{array}{ccc}1/4 \end{array}\right]$ equals 50 miles, then we would do this multiplied by . . . .

So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do $\left[\begin{array}{ccc}4*3=12\end{array}\right]$ and then from this, we would have to multiply this my 50.

The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.

$\left[\begin{array}{ccc}12*50\end{array}\right] =\left[\begin{array}{ccc}\boxed{\boxed{600}} \ so \ far!\end{array}\right]$

So, now, we have covered 3 as a whole, then we would have to see how 3/8 and also 1/4 can relate to each other.

So, in this case, $\boxed{\boxed{ \frac{3}{8} \ would \ be \ almost \ \boxed{half} \\ \ because \ it \ is \ almost \frac{4}{8} }}$

So, most likely, it would stay the same as it is, 1/4 because this is almost half to.

SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .

$\left[\begin{array}{ccc}\left[\begin{array}{ccc}\boxed{\boxed{600+50 \ or \frac{1}{4}=650}} \end{array}\right]\end{array}\right]$

YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .

$\left[\begin{array}{ccc}650 \ miles\end{array}\right]$

Hope this helps you fish Girl! :)

8 0

3 years ago

Read 2 more answers

What is the maximum number of relative extrema a polynomial function can have?

creativ13 [48]

Relative extrema occur where the derivative is zero (at least for your polynomial function). So taking the derivative we get

<span>20<span>x3</span>−3<span>x2</span>+6=0

</span><span> This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>

4 0

3 years ago

What is the height of this triangular prism?

chubhunter [2.5K]

The height will be four, becaus 5 is the height of the base not the whole prism. You can tell be beacause when you find the area of the base and multiply it by the height you multiply it by 4 not 5.

5 0

3 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago