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Whitepunk [10]
3 years ago
12

I need to know the answer to 2 1/3 x 4/5

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

Simplify the expression.

Exact Form:

28/15

Decimal Form:

1.8¯6

Mixed Number Form:

1 13/15

Step-by-step explanation:

lana66690 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Convert 2 1/3 to improper fraction

2\dfrac{1}{3}*\dfrac{4}{5}=\dfrac{7}{3}*\dfrac{4}{5}\\\\\\=\dfrac{7*4}{3*5}\\\\\\=\dfrac{28}{15}\\\\= 1\dfrac{13}{15}

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Alinara [238K]

Answer:

3,535 cm

Step-by-step explanation:

55cm=88km

Let's make that "one unit" - 55cm=1 unit. How many units are in the distance 5656km?

5656km/88km=64.2727... units.

55cmx64.2727... = 3,534.999 cm (depending on what your teacher requires, we can probably round to 3,535).

Therefore, we know that the two cities are 3,535 cm apart on the map.

6 0
2 years ago
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I need the answer and the work! <br> you have to find n.
zloy xaker [14]

Tell you what I'll do:  I'll show you the work, for two of them.
Then, knowing how to do it, you'll find the answers.
Deal ?

#1). n + (-13) = -12

Remove the parentheses
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Add  13  to each side:           n        =    1

================================

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OK.  Look those over, understand how they're done, then TAKE IT !

6 0
3 years ago
John is twice as old as Fred. Four years ago John was 6 times as old. How old is John?
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3 years ago
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What two pencils do i need to move to make three triangles?
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3 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

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3 years ago
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