Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
52×40=2080
You will work 2080hours in the year
Answer:
the number -5 is a real number
Step-by-step explanation:
real numbers are basically all numbers.... if you havent met complex numbers yet..
hopefuly this helped
:)
Try maybe just try hello reply back asap
It is number 1 and number 2 because the equation is 242× 62 and Number 1 and 2 are just breaking it down