Answer:
As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).
Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.
Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.
So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!
Step-by-step explanation:
The answer is .4x because -3.4x+3.8x
To solve this question, use the Cube surface area formula
Area = 6a^2 in which a = edge.
edge = 8.5
Area = 6(8.5)²
Simplify. Follow PEMDAS
Area = 6(72.25)
Area = 433.5
(C) 433.5 in² is your answer
hope this helps
Answer: C
Step-by-step explanation:
You can write each term into a fraction.
![\sqrt[5]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E4%7D)
becomes 
When you multiply 2 terms with the same base, you add the exponents.
is also the same as ![x\sqrt[5]{x^3}](https://tex.z-dn.net/?f=x%5Csqrt%5B5%5D%7Bx%5E3%7D)
You get this because ![\sqrt[5]{x^8} =\sqrt[5]{x*x*x*x*x*x*x*x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E8%7D%20%3D%5Csqrt%5B5%5D%7Bx%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%7D)
. When you pull out 5 os x, you are left with x³ on the inside.
Answer:
Step-by-step explanation:
C
