(13/4)*3 = 39/4 ft
I believe that's the answer
Answer:
x = 21°
y = 29°
Step-by-step explanation:
a) Solving for x
Note that:
(3x - 3)° and 60° are Alternate interior angles, and alternate interior angles are equal to each other, hence:
3x - 3 = 60° (Alternate interior angles)
Add 3 to both sides
3x - 3 +3 = 60 + 3
3x = 63°
x = 63°/3
x = 21°
b) Solving for y
Notes that:
(3x - 3)° and (4y + 4)° are Consecutive interior angles and the sum consecutive interior angles is 180°
3x - 3 + 4y + 4 = 180°
3x + 4y - 3 + 4 = 180°
3x + 4y + 1 = 180°
Note that x = 21
Hence
3(21) + 4y + 1 = 180°
63 + 1 + 4y = 180°
64 + 4y = 180°
Subtract 64 from both sides
64 - 64 + 4y = 180° - 64
4y = 116°
y = 116/4
y => 29°
Answer:
144 feet to nearest foot.
Step-by-step explanation:
Let the distance between Albert and the point on the ground that the balloon is directly above be x feet Then for Isaac the distance is 400 - x feet
So we have 2 right angled triangles and:
tan 62 = h/x
tan 48 = h / (400- x) where h is the height of the balloon.
From the first equation x = h / tan 62 so plugging this into the second one:
tan 48 = h / ( 400 - h/tan 62)
h = 400 tan 48 - h tan 48 tan 62
h + h tan 48 tan 62 = 400 tan 48
h ( 1 + tan48 tan62) = 400 tan48
h = 400 tan 48 / (1 + tan 48 tan 62)
= 143.8 feet.
