21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
81 Pesos
Step-by-step explanation:
Use a proportion.
$3 is to 2 Pesos as $121.10 is to x Pesos.
3/2 = 121.1/x
3x = 2 * 121.1
3x = 242.20
x = 80.7333...
Answer: 81 Pesos
Answer:
for both q I think is 12.5% but Im not that sure I'm sorry
Answer:
Yes
Step-by-step explanation:
I got it right.
