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aliina [53]
2 years ago
11

What is the vertex of the absolute value function below?

Mathematics
1 answer:
laiz [17]2 years ago
3 0

Answer:

(-3, 2)

Step-by-step explanation:

I think because of the vertex

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Four persons each bought a balloon at the circus. The table shows th amount of money each person have cashier and the amount eac
DaniilM [7]
You didn’t show the table. There’s not enough information.
4 0
2 years ago
Solve: 5x-4=6 please help meee
marta [7]

Answer:

x=2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the total surface area of the figure shown?
4vir4ik [10]

Given:

Composite figure.

The figure splitted into two shapes.

One is vertical cuboid and other is horizontal cuboid

To find:

Total surface area of the figure

Solution:

<u>Vertical cuboid:</u>

Length = 14 inches

Width = 12 inches

Height = 24 inches

Surface area = 2(lw + wh + lh)

                     = 2(14 × 12 + 12 × 24 + 14 × 24)

                     = 2(168 + 288 + 336)

Surface area = 1584 square inches

<u>Horizontal cuboid:</u>

Length = 14 inches

Width = 10 inches

Height = 30 - 12 = 18 inches

Surface area = 2(lw + wh + lh)

                     = 2(14 × 10 + 10 × 18 + 14 × 18)

                     = 2(140 + 180 + 252)

Surface area = 1144 square inches

Total surface area = 1584 + 1144

                              = 2728 square inches

The total surface area of the figure is 2728 square inches.

4 0
3 years ago
How tall is the green character?
vodomira [7]

My guess......... um 5'4

5 0
3 years ago
Using the given information, give the vertex form equation of each parabola.
Amanda [17]

Answer:

The equation of parabola is given by : (x-4) = \frac{-1}{3}(y+3)^{2}

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:(\frac{47}{12},-3)

The general equation of parabola is given by.

(x-h)^{2} = 4p(y-k), When x-componet of focus and Vertex is same  

(x-h) = 4p(y-k)^{2}, When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

For value of p:

p=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

p=\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}

p=\sqrt{(\frac{1}{12})^{2}}

p=\frac{1}{12} and p=\frac{-1}{12}

Since, Focus is left side of the vertex,

p=\frac{-1}{12} is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p=\frac{-1}{12}

(x-h) = 4p(y-k)^{2}

(x-4) = 4(\frac{-1}{12})(y+3)^{2}

(x-4) = \frac{-1}{3}(y+3)^{2}

8 0
3 years ago
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