Answer:
$3360 combined. $1560 from acct b and $2100 from acct a
Answer:
The standard deviation of the new data will be increased as compared to the previous standard deviation of the data.
Step-by-step explanation:
The prices are given to be : 59, 60, 65, 99, 175
Standard deviation = $49
Now, if we add or subtract any constant value to each of the terms then the standard deviation remains unchanged.
But, we add a new price in the given data that is $450
![\text{New standard deviation = }\sqrt{\frac{\sum (\bar{x}-x_i)^2}{n}}\\\\\bar{x}\text{ is the mean of data after adding 450 and}\\x_i\text{ are the price values of the sample data}](https://tex.z-dn.net/?f=%5Ctext%7BNew%20standard%20deviation%20%3D%20%7D%5Csqrt%7B%5Cfrac%7B%5Csum%20%28%5Cbar%7Bx%7D-x_i%29%5E2%7D%7Bn%7D%7D%5C%5C%5C%5C%5Cbar%7Bx%7D%5Ctext%7B%20is%20the%20mean%20of%20data%20after%20adding%20450%20and%7D%5C%5Cx_i%5Ctext%7B%20are%20the%20price%20values%20of%20the%20sample%20data%7D)
Hence, Standard deviation is calculated to be 139.5
Therefore, the standard deviation of the new data will be increased as compared to the previous standard deviation of the data.
X - the number of plants in 8 in pots
y - the number of plants in 10 in pots
![x+y=6\\ 5x+8y=36\\\\ x=6-y\\ 5x+8y=36\\ 5(6-y)+8y=36\\ 30-5y+8y=36\\ 3y=6\\ y=2\\\\ x+2=6\\ x=4](https://tex.z-dn.net/?f=x%2By%3D6%5C%5C%0A5x%2B8y%3D36%5C%5C%5C%5C%0Ax%3D6-y%5C%5C%0A5x%2B8y%3D36%5C%5C%0A5%286-y%29%2B8y%3D36%5C%5C%0A30-5y%2B8y%3D36%5C%5C%0A3y%3D6%5C%5C%0Ay%3D2%5C%5C%5C%5C%0Ax%2B2%3D6%5C%5C%0Ax%3D4)
4 plants in 8 in pots and 2 in 10 in pots.
-2x^3-x^2-6x-7
I don't really know what else